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JEE Mains 1-Feb-2023 Shift 2 Solved Paper
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© examsnet.com
Question : 25
Total: 90
A square shaped coil of area
70
cm
2
having 600 turns rotates in a magnetic field of
0.4
wbm
−
2
, about an axis which is parallel to one of the side of the coil and perpendicular to the direction of field. If the coil completes 500 revolution in a minute, the instantaneous emf when the plane of the coil is inclined at
60
∘
with the field, will be ______ V. (Take
π
=
22
7
)
[1-Feb-2023 Shift 2]
Your Answer:
Validate
Solution:
N
=
600
,
A
=
70
×
10
−
4
m
2
,
B
=
0.4
T
ω
=
500
×
2
π
60
=
100
π
6
rad
∕
s
E
=
NAB
ω
s
i
n
ω
t
ω
t
is angle
b
∕
w
→
A
&
→
B
=
600
×
70
×
10
−
4
×
0.4
×
100
π
6
×
1
2
=
44
V
© examsnet.com
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