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JEE Mains 1-Feb-2023 Shift 2 Solved Paper
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© examsnet.com
Question : 51
Total: 90
0.3
g
of ethane undergoes combustion at
27
∘
C
in a bomb calorimeter. The temperature of calorimeter system (including the water) is found to rise by
0.5
∘
C
. The heat evolved during combustion of ethane at constant pressure is _______
kJ
mol
−
1
.
(Nearest integer)
[Given: The heat capacity of the calorimeter system is
20
kJ
K
−
1
,
R
=
8.3
JK
−
1
mol
−
1
.
Assume ideal gas behaviour.
Atomic mass of
C
and
H
are 12 and
1
g
mol
−
1
respectively]
[1-Feb-2023 Shift 2]
Your Answer:
Validate
Solution:
(Bomb calorimeter
→
const volume
Heat released
By combustion of 1 mole
C
2
H
6
(
∆
U
)
=
−
20
×
0.5
0.3
×
30
=
−
1000
kJ
C
2
H
6
(
g
)
+
7
∕
2
O
2
(
g
)
→
2
CO
2
(
g
)
+
3
H
2
O
(
l
)
∆
ng
=
2
−
(
2
+
7
∕
2
)
=
−
(
7
∕
2
)
∆
H
=
∆
U
+
∆
nRT
=
−
1000
−
7
∕
2
×
8.3
×
300
kJ
=
−
1000
−
6.225
=
−
1006
kJ
So heat released
=
1006
kJ
mol
−
1
© examsnet.com
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