Let a, ar,ar2 be three terms of GP Given : a2+(ar)2+(ar2)2=33033 ‌a2(1+r2+r4)=112.3.7.13 ‌⇒a=11‌ and ‌1+r2+r4=3.7.13 ‌⇒r2(1+r2)=273−1 ‌⇒r2(r2+1)=272=16×17 ‌⇒r2=16 ‌∴r=4‌‌[∵r>0] Sum of three terms =a+ar+ar2=a(1+r+r2) ‌=11(1+4+16) ‌=11×21=231