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Test Index
JEE Mains 25-Jan-2023 Shift 2 Solved Paper
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© examsnet.com
Question : 4
Total: 90
For a moving coil galvanometer, the deflection in the coil is
0.05
rad
when a current of
10
mA
is passed through it. If the torsional constant of suspension wire is
4.0
×
10
−
5
Nm
rad
−
1
, the magnetic field is
0.01
T
and the number of turns in the coil is 200 , the area of each turn (in
cm
2
) is :
[25-Jan-2023 Shift 2]
2.0
1.0
1.5
0.5
Validate
Solution:
τ
=
K
θ
NiAB
=
K
θ
A
=
K
θ
NiB
=
4
×
10
−
5
×
0.05
200
×
10
×
10
−
3
×
0.01
On solving
A
=
10
−
4
m
2
=
1
cm
2
© examsnet.com
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