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JEE Mains 25-July-2022 Shift 2 Solved Paper
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© examsnet.com
Question : 5
Total: 90
The sum
21
∑
n
=
1
3
(
4
n
−
1
)
(
4
n
+
3
)
is equal to
[25-Jul-2022-Shift-2]
7
87
7
29
14
87
21
29
Validate
Solution:
👈: Video Solution
21
∑
n
=
1
3
(
4
n
−
1
)
(
4
n
+
3
)
=
3
4
21
∑
n
=
1
1
4
n
−
1
−
1
4
n
+
3
=
3
4
[
(
1
3
−
1
7
)
+
(
1
7
−
1
11
)
+
.
.
.
+
(
1
83
−
1
87
)
]
=
3
4
[
1
3
−
1
87
]
=
3
4
84
3.87
=
7
29
© examsnet.com
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