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JEE Mains 26-July-2022 Shift 2 Solved Paper
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© examsnet.com
Question : 9
Total: 90
∫
0
20
π
(
|
sin
x
|
+
|
cos
x
|
)
2
d
x
is equal to
[26-Jul-2022-Shift-2]
10
(
π
+
4
)
10
(
π
+
2
)
20
(
π
−
2
)
20
(
π
+
2
)
Validate
Solution:
👈: Video Solution
I
=
∫
0
20
π
(
|
sin
x
|
+
|
cos
x
|
)
2
d
x
=
20
∫
0
π
(
1
+
|
sin
2
x
|
)
d
x
=
40
∫
0
π
2
(
1
+
sin
2
x
)
d
x
=
.40
(
x
−
cos
2
x
2
)
|
0
π
2
=
40
(
π
2
+
1
2
+
1
2
)
=
20
(
π
+
2
)
© examsnet.com
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