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JEE Mains 27-July-2022 Shift 1 Solved Paper
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© examsnet.com
Question : 38
Total: 90
Read the following statements :
A. When small temperature difference between a liquid and its surrounding is doubled, the rate of loss of heat of the liquid becomes twice.
B. Two bodies
P
and
Q
having equal surface areas are maintained at temperature
10
∘
C
and
20
∘
C
. The thermal radiation emitted in a given time by
P
and
Q
are in the ratio
1
:
1.15
.
C. A Carnot Engine working between
100
K
and
400
K
has an efficiency of
75
%
.
D. When small temperature difference between a liquid and its surrounding is quadrupled, the rate of loss of heat of the liquid becomes twice.
Choose the correct answer from the options given below :
[27-Jul-2022-Shift-1]
A, B, C only
A, B only
A, C only
B, C, D only
Validate
Solution:
Heat Transfer
A. by Newton's low of colling
d
θ
dt
=
∝
∆
T
B.
H
=
d
θ
dt
=
σ
eAT
T
4
⇒
H
P
H
Q
=
(
T
P
T
Q
)
4
=
(
283
293
)
4
H
P
:
H
Q
=
1
(
1.03
)
4
=
1
:
(
1.03
)
4
=
1
:
1.15
⇒
B
is correct
C.
η
=
1
−
100
400
=
3
4
=
75
%
D. is wrong as
d
θ
dt
∝
∆
T
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