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JEE Mains 27-July-2022 Shift 1 Solved Paper
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© examsnet.com
Question : 45
Total: 90
A beam of light travelling along
X
-axis is described by the electric field
E
y
=
900
sin
ω
(
t
−
x
∕
c
)
.
The ratio of electric force to magnetic force on a charge q moving along
Y
-axis with a speed of
3
×
10
7
ms
−
1
will be :
(Given speed of light
=
3
×
10
8
ms
−
1
)
[27-Jul-2022-Shift-1]
1
:
1
1
:
10
10
:
1
1
:
2
Validate
Solution:
E
y
=
900
sin
(
ω
t
−
ω
x
c
)
E
0
=
900
F
E
=
qE
0
F
B
=
qvB
0
F
E
F
B
=
E
0
vB
0
=
c
v
=
3
×
10
8
3
×
10
7
=
10
:
1
© examsnet.com
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