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JEE Mains 29-July-2022 Shift 2 Solved Paper
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© examsnet.com
Question : 63
Total: 90
C
(
s
)
+
O
2
(
g
)
→
CO
2
(
g
)
+
400
k
.
J
C
(
s
)
+
1
2
O
2
(
g
)
→
CO
(
g
)
+
100
kJ
When coal of purity
60
%
is allowed to burn in presence of insufficient oxygen,
60
%
of carbon is converted into '
CO
' and the remaining is converted into '
CO
2
'. The heat generated when
0.6
kg
of coal is burnt is _______.
[29-Jul-2022-Shift-2]
1600
kJ
3200
kJ
4400
kJ
6600
kJ
Validate
Solution:
Weight of coal
=
0.6
kg
=
600
gm
∴
60
%
of it is carbon
So weight of carbon
=
600
×
60
100
=
360
g
∴
moles of carbon
=
360
12
=
30
moles
∴
Heat generated
=
12
×
400
+
18
×
100
=
6600
kJ
© examsnet.com
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