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JEE Mains 30-Jan-2023 Shift 1 Solved Paper
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© examsnet.com
Question : 5
Total: 90
Choose the correct relationship between Poisson ratio
(
σ
)
. bulk modulus
(
K
)
and modulus of rigidity
(
η
)
of a given solid object:
[30-Jan-2023 Shift 1]
σ
=
3
K
−
2
η
6
K
+
2
η
σ
=
6
K
+
2
η
3
K
−
2
η
σ
=
3
K
+
2
η
6
K
+
2
η
σ
=
6
K
−
2
η
3
K
−
2
η
Validate
Solution:
Y
=
3
η
(
1
+
σ
)
Y
=
3
K
(
1
−
σ
)
⇒
2
η
(
1
+
σ
)
=
3
K
(
1
−
2
σ
)
⇒
σ
=
(
3
K
−
2
η
6
K
+
2
η
)
© examsnet.com
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