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JEE Mains 31-Jan-2023 Shift 2 Solved Paper
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© examsnet.com
Question : 22
Total: 90
Two light waves of wavelengths 800 and
600
nm
are used in Young's double slit experiment to obtain interference fringes on a screen placed
7
m
away from plane of slits. If the two slits are separated by
0.35
mm
, then shortest distance from the central bright maximum to the point where the bright fringes of the two wavelength coincide will be _______
mm
.
[31-Jan-2023 Shift 2]
Your Answer:
Validate
Solution:
ω
1
=
λ
1
D
d
and
ω
2
=
λ
2
D
d
ω
1
=
16
mm
and
ω
2
=
12
mm
So
LCM
(
ω
1
,
ω
2
)
=
48
mm
So at
48
mm
distance both bright fringes will be found.
© examsnet.com
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