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JEE Mains 31-Jan-2023 Shift 2 Solved Paper
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© examsnet.com
Question : 9
Total: 90
The number of turns of the coil of a moving coil galvanometer is increased in order to increase current sensitivity by
50
%
. The percentage change in voltage sensitivity of the galvanometer will be:
[31-Jan-2023 Shift 2]
100
%
50
%
75
%
0
%
Validate
Solution:
Current sensitivity
=
Voltage sensitivity
×
R
Current sensitivity is made
1.5
times.
R
also increase
1.5
times.
Hence voltage sensitivity
=
1.5
×
current sensitivity
1.5
×
R
=
no change
© examsnet.com
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