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JEE Mains 6-Apr-2023 Shift 1 Solved Paper
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© examsnet.com
Question : 36
Total: 90
A particle is moving with constant speed in a circular path. When the particle turns by an angle
90
∘
, the ratio of instantaneous velocity to its average velocity is
π
:
x
√
2
. The value of
x
will be -
[6-Apr-2023 shift 1]
7
2
1
5
Validate
Solution:
👈: Video Solution
V
A
=
v
^
𝑗
And
V
B
=
−
v
^
𝑖
Time to reach from
A
to
B
=
2
π
R
4
×
1
v
=
π
R
2
v
Displacement from
A
to
B
=
R
√
2
Now, Average velocity from
A
to
B
=
Displacement
Time
=
R
√
2
π
R
2
v
=
2
√
2
v
π
Instantaneous velocity at
B
is
−
v
^
𝑖
According to question,
instantaneous velocity
average velocity
=
π
x
√
2
v
2
√
2
v
π
=
π
x
√
2
⇒
π
2
√
2
=
π
x
√
2
⇒
x
=
2
© examsnet.com
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