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JEE Mains 6-Apr-2023 Shift 1 Solved Paper
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© examsnet.com
Question : 5
Total: 90
A pair of dice is thrown 5 times. For each throw, a total of 5 is considered a success. If probability of at least 4 successes is
k
3
11
, then
k
is equal to :
[6-Apr-2023 shift 1]
164
123
82
75
Validate
Solution:
n
(
total
5
)
=
{
1
,
4
)
,
(
2
,
3
)
,
(
3
,
2
)
,
(
4
,
1
)
}
=
4
P
(
success
)
=
4
36
=
1
9
P
(
at least
4
success
)
=
P
(
4
success
)
+
P
(
5
success
)
=
5
C
4
⋅
(
1
9
)
⋅
8
9
+
5
C
5
(
1
9
)
5
=
41
9
5
=
41
3
10
=
123
3
11
=
k
3
11
K
=
123
© examsnet.com
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