If elements are not repeated, then number of elements in A1∪A2∪A3 ..... ∪A30 is 30 × 5 But each element is used 10 times. So, S =
30×5
10
= 15 If elements in B1,B2,B3 .... ∪Bn are not repeated , then the total number of elements in B1∪B2∪B3 ..... ∪Bn is 3n But each element is repeated 9 times So, S =