=0.6298 No. of gram equivalents from the current (Q) =I×t=140×482.5=67550C No. of gram equivalents=
67550
96500
=0.7 Since only Cu and Fe are dissolved from the anode no. of gram equivalents of Fe =0.7−0.6928 =0.0072 Therefore, mass of Fe =0.0072×27.75 =0.1998g % of Fe =