Given that,x=t2+3t−8→ (1) y=2t2−2t−5 → (2) At point (2, −1), Eq. (2) becomes −1=2t2−2t−5 ⇒2t2−2t−4=0 ⇒t2−t−2=0 ⇒(t−2)(t+1)=0 ⇒t=2,−1 → (3) Similarly, at point (2, −1) Eq. (1) becomes 2=t2+3t−8 ⇒t2+3t−10=0 ⇒(t+5)(t−2)=0 ⇒t=2,−5 → (4) From Eqs. (3) and (4), we have common value of t = 2. Now,