Given, maximum speed,vmax=0.5ms−1; maximum acceleration,amax=1.0ms−1; angular frequency, ω=? Now, we know vmax=ωA → (1) where A is amplitude of oscillation. Also,amax=ω2A → (2) Using Eqs. (1) and (2), we get
vmax
amax
=
ωA
ω2A
⇒
vmax
amax
=
1
ω
⇒ω=
amax
vmax
=
1.0
0.5
⇒ω=2rads−1 Therefore, angular frequency of oscillation is 2rads−1