Given, horizontal component of Earth’s magnetic field = 3.0 G; angle of dip = 30° Now, horizontal component = B cos (angle of dip) ⇒3.0G=Bcos30° ⇒B=
3.0
cos30∘
=
3.0×2
√3
⇒B=2√3=3.464∼3.5G Therefore, magnetic field of Earth at that location = 3.5 G