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KCET 2020 Physics Solved Paper
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© examsnet.com
Question : 13
Total: 60
The following figure shows a beam of light converging at point P. When a concave lens of focal length 16 cm is introduced in the path of the beam at a place shown by dotted line such that OP becomes the axis of the lens, the beam converges at a distance 𝑥 from the lens. The value of x will be equal to
48 cm
12 cm
24 cm
36 cm
Validate
Solution:
So, here when we put the concave lens, let the beam will converge at a distance
x
=
v
Using lens formulae, we have,
1
f
=
1
v
−
1
u
Where
u
=
12
c
m
and
f
=
−
16
c
m
is given
∴
1
v
=
1
f
+
1
u
=
−
1
16
+
1
12
=
1
48
c
m
⇒
v
=
48
c
m
Hence,
x
=
48
c
m
© examsnet.com
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