Given, vapour pressure of pure liquid A, pA=450mm of Hg Vapour pressure of pure liquid B, p°B=700mm of Hg Total vapour pressure, pTotal=600mm of Hg From Raoult's law, pTolal=p°AχA+pBχB =p°AχA+p°B(1−χA) ⇒ 600=450χA=700(1−χA) =450χA+700−700χA =700−250χA 250χA=700−600 ⇒χA=