To find the minimum value of the expression f(x)=1−sinx, we start by considering the range of the sine function. Since −1≤sinx≤1, this means the minimum value of sinx is -1 . Now, compute f(x) when sinx=−1 : f(x)=1−(−1)=1+1=2 Check if sinx=1 : f(x)=1−1=0 Thus, the minimum value of f(x)=1−sinx occurs when sinx=1, making the minimum value: fmin=0