......(i) since, curve passes through the point (2,-1) . ∴t2+3t−8=2 and 2t2−2t−5=−1 ⇒t2+3t−10=0 and 2t2−2t−4=0 ⇒t2+5t−2t−10=0 and t2−t−2=0 ⇒(t+5)(t−2)=0 and (t2−2t+t−2)=0 ⇒t=−5,2 and (t−2)(t+1)=0 ⇒t=−5,2 and t=−1,2 So, common value of t is 2 . On putting t=2 in Eq. (i), we get [