=0.00625‌ moles ‌ Here, CH3 - of CH3MgBr combines with H -atom of R−OH to give CH4. ∴n(CH4)=n(R−OH) Also, n‌‌=‌
W
M(‌ molar mass ‌)
0.00625‌‌=‌
375×10−3
M
∴M=‌
375
0.00625×1000
=60 Also, general formula for alcohol =CnH2n+1⋅OH Thus, 12n+2n+1+17=60‌‌(∵OH=16+1=17) ∴‌‌14n=60−18=42 ∴‌‌n=3 Hence, alcohol is n -propanol (C3H7OH).