(d) In a consistent, the intersection point of two lines, satisfy the third line. Consider λ=−1, then given equation become −x−y=22x−3y=1⇒x=−1,y=−1Third equation is 3x−2y=−1 Put x=−1,y=−1∴−3+2=−1⇒−1=−1, true Consider λ=4, then given equation become 4x−y=22x−3y=−4⇒y=2,x=1 Third equation is 3x−2y=−1 Put y=2,x=1∴3−4=−1⇒−1=−1, true Hence option (d) is correct.