Total charge produced by cell =1A×(5951×3600)s =2142360C ∵96500C=1mol ∴2142360C=
2142360
96500
=22.20mol of e− Now, in H2−O2, fuel cell following reaction occurs, At anode
2H2(g)+4O−H(aq)⟶4H2O(h+4e−
At cathode
O2(g)+2H2O(l)+4e−⟶4OH−(aq)
Overall reaction 2H2(g)+O2(g)⟶2H2O⟨n Thus, from above reaction it is clear that 2mol of e−≡1mol of H2O ∵22mol of e−≡11mol of H2O =(11×18)g of H2O [∵ No. of moles =