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KEAM 2019 Physics and Chemistry Paper
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© examsnet.com
Question : 47
Total: 120
A brick of mass 2kg slides down an incline of height 5m and angle 30°. If the coefficient of friction of the incline is
1
2
√
3
, the velocity of the block at the bottom of the incline is (Assume the acceleration due to gravity is 10 m/
s
2
)
5 m/s
50 m/s
7 m/s
0
10 m/s
Validate
Solution:
Key idea Acceleration of block sliding down a rough inclined plane as shown in the figure, is given by
a
=
g
(
sin
θ
−
µ
cos
θ
)
Given, mass of brick
m
=
2
k
g
,
height of plane
H
=
5
m
,
θ
=
30
∘
and coefficient of friction
µ
=
1
2
√
3
∴
a
=
g
(
sin
30
∘
−
1
2
√
3
cos
30
∘
)
⇒
a
=
10
[
1
2
−
1
4
]
=
2.5
m
/
s
2
Length of inclined plane
x
=
H
sin
θ
=
5
×
sin
30
∘
=
10
m
From 3rd equation of motion
v
2
−
u
2
=
2
a
s
⇒
v
=
√
2
a
s
⇒
v
=
√
2
×
25
×
10
=
√
50
=
7.07
So, nearby correct option is (c).
© examsnet.com
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