Buoyancy force on a body is given as Fb=ρVg where, ρ= fluid density, V= Volume of liquid, which displaced by body. ∵g=9.806m/s2 So, for aluminium piece FA=ρliq(0.5m3)9.8...(i) Similarly, for lead FL=ρliq (0.5m3)9.8....(ii) Hence, from Eqs. (i) and (ii), we get FA=FL