Given, length of conductor, l=20cm=0.2m Current, i=5A, θ=30∘ Magnetic field, B=0.5T Force acting on the conductor in the external magnetic field is given as F=il×B In terms of magnitude, F=ilBsinθ Substituting the given values, we get F=5×0.2×0.5×sin30∘ =5×0.2×0.5×