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KVPY 2019 SA Exam Previous Papers
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© examsnet.com
Question : 67
Total: 80
In an hour–glass approximately 100 grains of sand fall per second (starting from rest), and it takes 2 sec. for each sand particle to reach the bottom of the hour–glass. If the average mass of each sand particle is 0.2 g then the average force exerted by the falling sand on the bottom of the hour–glass is close to :
0.4 N
0.8 N
1.2 N
1.6 N
Validate
Solution:
Velocity of sand particle just before striking the bottom is v = u + at
v = 0 + 10 × 2 = 20 m/s
p
i
= (0.2 × 10
–
3
) × 20
p
f
=
0
|
∆
p
|
=
4
×
10
–
3
k–m/s
f
avg
=
|
∆
p
|
∆
t
×
n
=
4
×
10
−
3
×
100
1
= 0.4 N
© examsnet.com
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