)aηbrc, V → volume P → pressure η → coefficient of viscosity r → radius Using dimensional analysis
[M0L3T–1]=[M1L−2T−2]a[M1L−1T−1]b[L]c
[M0L3T−1]=[Ma+bL−2a−b+cT−2a−b] a + b = 0 ...(1) –2a – b + c = 3 ...(2) a = –b –2a – b = – 1 ...(3) put the value of – 2a – b = –1 in equation (2) –1 + c = 3 c = 4 put a = – b in equation (3) 2b – b = –1 ⇒ b = –1 and a = 1 hence option (A) is correct.