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KVPY SA Exam 2016 Question Paper
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© examsnet.com
Question : 69
Total: 80
A 20gm bullet whose specific heat is 5000 J / (kg-ºC) and moving at 2000 m/s plunges into a 1.0 kg block of wax whose specific heat is 3000 J /(kg-ºC). Both bullet and wax are at 25 ºC and assume that
(i) the bullet comes to rest in the wax and
(ii) all its kinetic energy goes into heating the wax. Thermal temperature of the wax in ºC is close to
28.1
31.5
37.9
42.1
Validate
Solution:
M
B
=
20
×
10
–
3
Kg
C
B
=
5000
J
Kg
−
º
C
V
=
2000
M
s
M
w
=
1
Kg
C
w
=
3000
J
∕
Kg
–
º
C
T
f
=
25
º
C
=
298
K
1
2
MV
2
=
M
w
C
w
Δ
T
w
+
M
B
C
B
Δ
T
B
=
1
2
M
B
V
2
=
M
w
C
w
(
Δ
T
w
)
+
M
B
C
B
Δ
T
B
⇒
1
2
×
20
×
10
−
3
×
4
×
10
6
= (ΔT) {1 × 3000 + 20 × 10
–
3
× 5000}
⇒
40
×
10
3
=
Δ
T
(
3000
+
100
)
Δ
T
=
40
×
10
3
3100
=
12.9
T
f
−
25
=
12.9
T
f
=
25
+
12.9
=
37.9
º
C
© examsnet.com
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