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KVPY SA Exam 2018 Question Paper
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© examsnet.com
Question : 21
Total: 80
A certain liquid has a melting point of –50º C and a boiling point of 150ºC. A thermometer is designed with this liquid and its melting and boiling points are designated as 0º L and 100ºL. The melting and boiling points of water on this scale are
25º L and 75º L, respectively
0º L and 100º L, respectively
20º L and 70º L, respectively
30º L and 80º L, respectively
Validate
Solution:
100°L = 200°C
1°L = 2°C
0°C = 25°L
100°C = 75°L
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