(a+b)×h=12 (a+b)×h=24 24 × 1 12 × 2 6 × 4 8 × 3 In height angle. ∆AED Possible height for integer sides. h = 4, 3 Case–I When h = 4 Then possible triplet (3, 4, 5) i.e. DE = 4, AE = 3, AD = 5 if AE = 3, 2b = 3 b = 3/2 (Not possible because b ∈ I) Case–II When h = 3 Then AE = 4, 2b = 4 b = 2 ∴ CD = 2, AB = 6 ∴ |AB−CD|=4