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KVPY SA Exam 2018 Question Paper
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© examsnet.com
Question : 72
Total: 80
The quantity of heat (in J) required to raise the temperature of 1.0 kg of ethanol from 293.45 K to the boiling point and then change the liquid to vapour at that temperature is closest to
[ Given : Boiling point of ethanol 351.45 K
Specific heat capacity of liquid ethanol 2.44 J g
–
1
K
–
1
Latent heat of vaporization of ethanol 855 J g
–
1
]
1.42 × 10
2
9.97 × 10
2
1.42 × 10
5
9.97 × 10
5
Validate
Solution:
q
=
m
c
∆
t
+
heat of vapourisation
=
1000
×
2.44
(
351.45
−
293.45
)
+
855
×
1000
J
=
9.97
×
10
5
J
© examsnet.com
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