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KVPY SB SX Exam 2011 Question Paper
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© examsnet.com
Question : 34
Total: 120
An electron collides with a free molecule initially in its ground state. The collision leaves the molecule in an excited state that is metastable and does not decay to the ground state by radiation. Let K be the sum of the initial kinetic energies of the electron and the molecule, and
→
P
the sum of their initial momenta. Let K' and
→
P
′
represent the same physical quantities after the collision. Then
K
=
K
′
,
→
P
=
→
P
′
K
>
K
′
,
→
P
=
→
P
′
K
=
K
′
,
→
P
≠
→
P
′
K
>
K
′
,
→
P
≠
→
P
′
Validate
Solution:
Collision of
e
–
lead to excitation of molecules
so Collision is inelastic
∴ K' < K and loss of kinetic energy go for excitation of molecules. Momentum remain conserved during collision.
→
P
=
→
P
′
© examsnet.com
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