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KVPY SX SB Exam 19-Nov-2017 Question Paper
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© examsnet.com
Question : 19
Total: 120
A spherical ball is kept at the corner of a rectangular room such that the ball touches two (Perpendicular) walls and lies on the floor. If a point on the sphere is at distances of 9, 16, 25 from the two walls and the floor, then a possible radius of the sphere is
13
15
26
36
Validate
Solution:
(
r
−
9
)
2
+
(
r
−
16
)
2
+
(
r
−
25
)
2
=
r
2
solving this
2
r
2
−
100
r
+
962
=
0
r
2
−
50
r
+
481
=
0
r = 37, r = 13
possible radius = 13
According to option
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