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KVPY SX SB Exam 20141 Question Paper
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© examsnet.com
Question : 29
Total: 120
A whistle emitting a loud sound of frequency 540 Hz is whirled in a horizontal circle of radius 2 m and at a constant angular speed o f 15 rad/s. The speed o f sound is 330 m/s.
The ratio of the highest to the lowest frequency heard by a listener standing at rest at a large distance from the center of the circle is
1.0
1.1
1.2
1.4
Validate
Solution:
v
1
and
v
2
are speed of whistle
|
v
1
|
=
|
v
2
|
=
ω
r
= 15 × 2
= 30 m/s
Maximum frequency heard →
Here,
f → original frequency (540 Hz)
v → speed of sound
v
s
→speed of whistle
f
max
=
f
[
v
v
−
v
s
]
Minimum frequency heard →
f
min
=
f
[
v
v
+
v
s
]
f
max
f
min
=
v
+
v
s
v
−
v
s
=
330
+
30
330
−
30
=
360
300
f
max
f
min
=
6
5
=
1.2
© examsnet.com
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