⇒n=2] M = 0.25 µg (remained) Carbon used ⇒ M0−M ⇒ 0.75 µg Number of moles =(
0.75×10−6
12
) Number of reaction =
0.75×10−6
12
×6.023×1023 =0.37×1017 reaction Energy from reaction =0.376×1017×0.96MeV =0.36×1017 =3.6×1016 MeV ≈4×1016 MeV Energy from annihilation =2m0c2(0.376×1017) ≈1.02(0.376×1017) MeV ≈4×1016 MeV Total energy =Ereaction+Eanhillation ET≈8×1016 MeV