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KVPY SX SB Exam 2016 Question Paper
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© examsnet.com
Question : 10
Total: 120
A sphere with centre O sits atop a pole as shown in the figure. An observer on the ground is at a distance 50m from the foot of the pole. She notes that the angles of elevation from the observer to points P and Q on the sphere are 30º and 60º, respectively. Then, the radius of the sphere in meters is
100
(
1
−
1
√
3
)
50
√
6
3
50
(
1
−
1
√
3
)
100
√
6
3
Validate
Solution:
DE = BC = r
tan
30
°
=
h
50
⇒
h
=
50
√
3
tan
60
°
=
h
+
r
50
−
r
⇒
√
3
(
50
−
r
)
=
h
+
r
⇒
√
3
(
50
−
r
)
=
50
√
3
+
r
⇒
100
=
(
3
+
√
3
)
r
⇒
r
=
100
3
+
√
3
=
50
(
1
−
1
√
3
)
© examsnet.com
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