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KVPY SX SB Exam 2018 Question Paper
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© examsnet.com
Question : 26
Total: 120
In a Young’s double slit experiment the amplitudes of the two waves incident on the two slits are A and 2A. If
I
0
is the maximum intensity, then the intensity at a spot on the screen where the phase difference between the two interfering waves is ϕ.
I
0
cos
2
(
ϕ
∕
2
)
I
0
3
sin
(
ϕ
∕
2
)
I
0
9
(
5
+
4
cos
2
(
ϕ
)
)
I
0
9
(
5
+
8
cos
2
(
ϕ
)
)
Validate
Solution:
I
1
=
k
A
2
=
I
;
I
2
=
4
k
A
2
=
4
I
I
0
=
(
√
I
1
+
√
I
2
)
2
;
I
0
=
9
I
I
=
I
+
4
I
+
2
√
I
+
4
I
+
cos
θ
=
5
I
+
4
I
cos
θ
=
I
0
9
(
5
+
4
cos
θ
)
© examsnet.com
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