Solution:
Given:
Two dice are thrown simultaneously
Formula used:
Probability = Number of favourable outcomes/Total number of outcomes
Calculation:
Favourable outcomes whose sum is even = (1, 1), (1, 3), (1, 5), (2, 2), (2, 4), (2, 6), (3, 1), (3, 3), (3, 5), (4, 2), (4, 4), (4, 6), (5, 1), (5, 3), (5, 5), (6, 2), (6, 4) and (6, 6)
Number of favourable outcomes = 18
Total number of outcomes = 6 × 6 = 36
Probability = 18/36 = 1/2
∴ The required probability is 1/2
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