Given equation: 25−625×125÷3+10 By interchanging the signs we get. Using BODMAS we get Option 1: - And + 25−625×125÷3+10 =25+625×125÷3−10 =25+625×125/3−10 =25+78125/3−10 =25+26041.6−10 =26066.6−10 =26056.6 Option 2: × and ÷ 25−625÷125×3+10 =25−5×3+10 =25−15+10 =35−15 = 20 Hence, the correct answer is × and ÷