Given: A Geometric Progression with first term ‘a’ = 16 and common ratio ‘r’ = 2. Concept Used: In this type of question, where ‘r’ > 1, then the sum of n terms of a G.P= Sn=
a(rn−1)
r−1
Formula Used: Sn=
a(rn−1)
r−1
n = 10 Calculation: Considering the given series 16, 32, 64, 128, ...... S10=
16(210−1)
2−1
⇒S10−16×1023=16368 ∴ Sum of first 10 terms of given series is 16368