(a) Radius of inner track = 100 m Radius of outer track = 102 m ∴ Distance covered by A = 2 x π x 100 = 200 π m Distance covered by B = 2 x π x102 = 204 π m Time taken by A = 1 min 30 s = 90 s Time taken by B = 1 min 32 s = 92 s ∴ SA=
200
90
π SB=
204
92
π SA:SB =
200
90
π :
204
92
π = 18400 : 18360 So, SA>SB i.e., speed of A is greater than B