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Manipal Entrance Test 2013 Chemistry Paper

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Question : 15

Total: 60

Calculate second electron affinity of oxygen for the process,
O−(g)+e−(g)→O2−(g)
by using the following data
(i) Heat of sublimation of
Mg(s) = +147.7 k J mol‌−1
(ii) Ionisation energy of Mg(g) to form
Mg‌2+(g) = +2189.0 k J mol‌−1
(iii) Bond dissociation energy for
O2 = +498.4 kJ mol‌−1
(iv) First electron affinity of
O(g) = -141.0 kJ mol‌−1
(v) Heat formation of
MgO =-601.7 kJ mol‌−1
(vi) Lattice energy of
MgO =-3791.0 kJ mol‌−1

235.6 kJ mol‌−1
468.7 kJ mol‌−1
544.4 kJ mol‌−1
744.4 kJ mol‌−1

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