Charge acquired by the plates of the capacito q0=CV=(10µF)×(50V)=500µC Now, let the charge distribution is as follows. Total charge on positive plate has now become 700 µC while that in negative plate is still - 500 µC,
Here, charges are in µC. Net electric field at point P is zero. ∴
(700−q)
2Aε0
+
q
2Aε0
+(
500−q
2Aε0
)=
q
2Aε0
⇒q=600µC ∴ Potential difference between the plates is ΔV=