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MHT CET 2021 Chemistry Solved Paper
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© examsnet.com
Question : 10
Total: 100
An organic compound on analysis gave
C
=
42.8
%
,
H
=
7.2
%
and
N
=
50
%
. Volume of
1
g
of the compound was found to be
50
m
L
at STP. Molecular formula of the compound is
C
2
H
4
N
2
C
12
H
24
N
12
C
16
H
32
N
16
C
4
H
8
N
4
Validate
Solution:
Given,
C
=
42.8
%
,
H
=
7.2
%
and
N
=
50
%
Element
%
Moles
Simplest ratio
Whole number
C
42.8
42.8
12
=
3.56
1
1
H
7.2
7.2
1
=
7.2
2
2
N
50
50
14
=
3.57
1
1
∴
Empirical formula
=
C
H
2
N
Empirical formula mass
=
28
Now, number of moles
=
volume given at STP
22400
m
L
=
50
22400
=
2.23
×
10
−
3
Also, number of moles
=
weight
molecular weight
⇒
Molecular weight
=
1
2.23
×
10
−
3
=
448
∴
n
=
molecular weight
empirical weight
=
448
28
=
16
Hence, molecular formula
=
(
empirical formula
)
n
=
(
C
H
2
N
)
16
=
C
16
H
32
N
16
© examsnet.com
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