)dy=−ex(cos2x−sin‌2‌x)dx On integrating both sides, we get y+log‌y=−excos2x+∫ex‌sin‌2‌x‌d‌x −∫ex‌sin‌2‌x‌d‌x+C ⇒‌‌y+log‌y=−excos2x+C At x=0 and y=1, 1+0=−e0‌cos‌0+C C=2 [given] ∴ Required solutions is y+log‌y=−excos2x+2 ⇒‌‌y+log‌y+excos2x=2