)+2=0 Equation of plane parallel to the given plane is −2x+y−3z=λ. . . (i) Since, plane (i) passes through the point (1,4,−2). Therefore this point satisfy the given plane. Put x=1,y−4 and z=−2 in Eq. (i) −2(1)+4−3(−2)=λ −2+4+6=λ λ=8 Put λ=8 in Eq. (i), we get −2x+y−3z=8 2x−y+3z+8=0